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Table 1 Iterative values of AK, Vatan Two-step, Thakur New and Picard-S iteration processes for mapping \(T(x)=\frac{x}{2},\) where \(\alpha _{n}=\beta _{n}=\frac{1}{4},\) for all n

From: On different results for new three step iteration process in Banach spaces

 

AK

Vatan Two-step

Thakur New

Picard-S

\(x_{0}\)

0.9

0.9

0.9

0.9

\(x_{1}\)

\(8.6133\times 10^{-2}\)

\(1.7227\times 10^{-1}\)

\(2.1797\times 10^{-1}\)

\(2.1797\times 10^{-1}\)

\(x_{2}\)

\(8.2432\times 10^{-3}\)

\(3.2973\times 10^{-2}\)

\(5.2789\times 10^{-2}\)

\(5.2789\times 10^{-2}\)

\(x_{3}\)

\(7.889\times 10^{-4}\)

\(6.3112\times 10^{-3}\)

\(1.2785\times 10^{-2}\)

\(1.2785\times 10^{-2}\)

\(x_{4}\)

\(7.55\times 10^{-5}\)

\(1.208\times 10^{-3}\)

\(3.0963\times 10^{-3}\)

\(3.0963\times 10^{-3}\)

\(x_{5}\)

\(7.2256\times 10^{-6}\)

\(2.3122\times 10^{-4}\)

\(7.499\times 10^{-4}\)

\(7.499\times 10^{-4}\)

\(x_{6}\)

\(6.9151\times 10^{-7}\)

\(4.4257\times 10^{-5}\)

\(1.8162\times 10^{-4}\)

\(1.8162\times 10^{-4}\)

\(x_{7}\)

\(6.618\times 10^{-8}\)

\(8.471\times 10^{-6}\)

\(4.3985\times 10^{-5}\)

\(4.3985\times 10^{-5}\)

\(x_{8}\)

\(6.3336\times 10^{-9}\)

\(1.6214\times 10^{-6}\)

\(1.0653\times 10^{-5}\)

\(1.0653\times 10^{-5}\)

\(x_{9}\)

\(6.0615\times 10^{-10}\)

\(3.1035\times 10^{-7}\)

\(2.5799\times 10^{-6}\)

\(2.5799\times 10^{-6}\)

\(x_{10}\)

\(5.801\times 10^{-11}\)

\(5.9402\times 10^{-8}\)

\(6.2483\times 10^{-7}\)

\(6.2483\times 10^{-7}\)