Table 1 Comparison between Neyrame et al. (2010) solutions and our solutions

i. If C₁ = 0 and u(ξ) = 4v₂₁(η), Case 1 becomes:

$\begin{array}{c}{v}_{2_1}\left(\Phi \right)=-2({\lambda }^2-4\mu ){coth}^2\left(\frac{\sqrt{{\lambda }^2-4\mu }\mathit{\xi }}{2}\right)+\frac{3\lambda }{2}+{\alpha }_0.\end{array}$

i. If A = 1, C = 0, Ω = λ²-4μ, B = 1, E = 1, V = 1, $\frac{20}{3}-\frac{3\lambda }{2}={\alpha }_0$ then the solution is

$v_{2_1}\left(\Phi \right)=-2({\lambda }^2-4\mu ){coth}^2\left(\frac{\sqrt{{\lambda }^2-4\mu }\xi }{2}\right)+\frac{3\lambda }{2}+{\alpha }_0.$

ii. If C₁ = 0 and u(ξ) = 4v₂₃(η), Case 2 becomes:

$v_{2_3}\left(\Phi \right)=-2(4\mu -{\lambda }^2){cot}^2\left(\frac{\sqrt{4\mu -{\lambda }^2}\xi }{2}\right)+\frac{3\lambda }{2}+{\alpha }_0.$

ii. If A = 1, C = 0, Ω = λ²-4 μ, B = 1, E = 1, V = 1, $\frac{20}{3}-\frac{3\lambda }{2}={\alpha }_0$ then the solution is

$v_{2_3}\left(\Phi \right)=-2(4\mu -{\lambda }^2){cot}^2\left(\frac{\sqrt{4\mu -{\lambda }^2}\xi }{2}\right)+\frac{3\lambda }{2}+{\alpha }_0.$

iii. If u(ξ) = 4v₂₅(η), Case 3 becomes:

$v_{2_5}\left(\Phi \right)=-2{\left(\frac{C_2}{C_1+C_2\eta }\right)}^2+\frac{3\lambda }{2}+{\alpha }_0.$

iii. If A = 1, C = 0, B = 1, E = 1, V = 1, $\frac{20}{3}-\frac{3\lambda }{2}={\alpha }_0$ then the solution is

$v_{2_5}\left(\Phi \right)=-2{\left(\frac{C_2}{C_1+C_2\eta }\right)}^2+\frac{3\lambda }{2}+{\alpha }_0.$