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Table 1 \(H=\frac{1}{6},\ h=\tau \)

From: Parallel algorithm for convection–diffusion system based on least-squares procedure

h

m

\(a=1\)

\(a=1\) e–2

\(a=1e{-}4\)

\(\Vert \cdot \Vert _2\)

\(\Vert \cdot \Vert _\infty \)

\(\Vert \cdot \Vert _2\)

\(\Vert \cdot \Vert _\infty \)

\(\Vert \cdot \Vert _2\)

\(\Vert \cdot \Vert _\infty \)

\(\frac{1}{48}\)

\(*\)

\(2.9866\) e–2

\(1.9250\) e–1

\(8.6118\) e−3

\(2.6493\) e–2

\(7.4344\) e−3

\(1.5421\) e–2

\(\frac{1}{48}\)

1

\(4.0090\) e–2

\(2.0819\) e–1

\(8.5534e{-}3\)

\(2.5531\) e–2

\(7.4495e{-}3\)

\(1.4833\) e–2

\(\frac{1}{48}\)

2

\(4.0086 \) e–2

\(1.7485\) e–1

\(8.6384e{-}3\)

\(2.5532\) e–2

\(7.4785e{-}3\)

\(1.5375\) e–2

\(\frac{1}{48}\)

3

\(4.1043\) e–2

\(1.7967\) e–1

\(8.6403e{-}3\)

\(2.5532\) e–2

\(7.4790e{-}3\)

\(1.5379\) e–2

\(\frac{1}{48}\)

4

\(4.1164\) e–2

\(1.7947\) e–1

\(8.6403e{-}3\)

\(2.5532 \) e–2

\(7.4790e{-}3\)

\(1.5379 \) e–2

\(\frac{1}{96}\)

\(*\)

\(1.4800\) e–2

\(9.5488\) e–2

\(4.9541e{-}3\)

\(2.5220\) e–2

\(3.6348e{-}3\)

\(7.4154e{-}3\)

\(\frac{1}{96}\)

1

\(1.7513\) e–2

\(1.0523\) e–1

\(4.9351e{-}3\)

\(2.4967\) e–2

\(3.6397e{-}3\)

\(7.3584e{-}3\)

\(\frac{1}{96}\)

2

\(1.7951\) e–2

\(9.1683\) e–2

\(4.9457e{-}3\)

\(2.4967\) e–2

\(3.6420e{-}3\)

\(7.4145e{-}3\)

\(\frac{1}{96}\)

3

\(1.8186\) e–2

\(9.3327\) e–2

\(4.9458e{-}3\)

\(2.4967\) e–2

\(3.6420e{-}3\)

\(7.4147 e{-}3\)

\(\frac{1}{96}\)

4

\(1.8219\) e–2

\(9.3540\) e–2

\(4.9458e{-}3\)

\(2.4967 \) e–2

\(3.6420e{-}3\)

\(7.4147e{-}3\)

\(\frac{1}{192}\)

\(*\)

\( 7.5407e{-}3\)

\( 4.7396\) e–2

\(2.9959e{-}3\)

\(2.0611\) e–2

\(1.8231e{-}3\)

\(4.2963e{-}3\)

\(\frac{1}{192}\)

1

\(7.9423e{-}3\)

\(5.1561\) e–2

\(2.9899e{-}3\)

\(2.0539\) e–2

\(1.8239e{-}3\)

\(4.2920e{-}3\)

\(\frac{1}{192}\)

2

\(8.1633e{-}3\)

\(4.7424\) e–2

\(2.9912e{-}3\)

\(2.0539\) e–2

\(1.8240e{-}3\)

\(4.2920e{-}3\)

\(\frac{1}{192}\)

3

\(8.1986e{-}3\)

\(4.7096\) e–2

\(2.9912e{-}3\)

\(2.0539\) e–2

\(1.8240e{-}3\)

\(4.2920e{-}3\)

\(\frac{1}{192}\)

4

\(8.2016 e{-}3\)

\(4.7458\) e–2

\(2.9912e{-}3\)

\( 2.0539\) e–2

\(1.8240e{-}3\)

\(4.2920e{-}3\)

  1. * The numerical results by least-squares algorithm